Hi Emily Logarithm! Love your presentation and transitions! (: However, the examples for odd and even functions can be more improved. For odd functions, it can be....'' Determine if the function is negative f(x)=2x^3-6x''. Let's solve it with the algebraic method of plugging in "-x". f(-x)= 2(-x)^3-6(-x) = -2x^3+6x = -(2x^3-6x) = -f(x) Therefore, f(x) is an odd function.For even functions, it can be....... ''Determine if the function is even f(x)= x^2-4''.Use the algebraic method by plugging in "-x" into the function.f(-x)= (-x)^2-4f(-x) x^2-4 f(-x)= f(x) Therefore, we can conclude that f(x) is an even function. Thank you.