Hi Emily Logarithm! Love your presentation and transitions! (: However, the examples for odd and even functions can be more improved. For odd functions, it can be....
'' Determine if the function is negative f(x)=2x^3-6x''.
Let's solve it with the algebraic method of plugging in "-x". f(-x)= 2(-x)^3-6(-x) = -2x^3+6x = -(2x^3-6x) = -f(x)
Therefore, f(x) is an odd function.
For even functions, it can be.......
''Determine if the function is even f(x)= x^2-4''.
Use the algebraic method by plugging in "-x" into the function. f(-x)= (-x)^2-4 f(-x) x^2-4 f(-x)= f(x)
Therefore, we can conclude that f(x) is an even function.
Hi Emily Logarithm! Love your presentation and transitions! (: However, the examples for odd and even functions can be more improved. For odd functions, it can be....
ReplyDelete'' Determine if the function is negative f(x)=2x^3-6x''.
Let's solve it with the algebraic method of plugging in "-x".
f(-x)= 2(-x)^3-6(-x)
= -2x^3+6x
= -(2x^3-6x)
= -f(x)
Therefore, f(x) is an odd function.
For even functions, it can be.......
''Determine if the function is even f(x)= x^2-4''.
Use the algebraic method by plugging in "-x" into the function.
f(-x)= (-x)^2-4
f(-x) x^2-4
f(-x)= f(x)
Therefore, we can conclude that f(x) is an even function.
Thank you.