tag:blogger.com,1999:blog-4642924809463633662.post5987798391231227029..comments2012-11-28T18:28:24.496-08:00Comments on Precalculus 2012 -2013: Chapter P Graphing FunctionsAnonymoushttp://www.blogger.com/profile/08132497271085410261noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-4642924809463633662.post-62531783508843887512012-10-25T01:41:48.172-07:002012-10-25T01:41:48.172-07:00Hi Emily Logarithm! Love your presentation and tra...Hi Emily Logarithm! Love your presentation and transitions! (: However, the examples for odd and even functions can be more improved. For odd functions, it can be....<br /><br />'' Determine if the function is negative f(x)=2x^3-6x''. <br /><br />Let's solve it with the algebraic method of plugging in "-x". <br />f(-x)= 2(-x)^3-6(-x) <br />= -2x^3+6x <br />= -(2x^3-6x) <br />= -f(x) <br /> <br />Therefore, f(x) is an odd function.<br /><br />For even functions, it can be....... <br /><br />''Determine if the function is even f(x)= x^2-4''.<br /><br />Use the algebraic method by plugging in "-x" into the function.<br />f(-x)= (-x)^2-4<br />f(-x) x^2-4 <br />f(-x)= f(x) <br /> <br />Therefore, we can conclude that f(x) is an even function. <br /><br />Thank you. <br /><br />Kowan103https://www.blogger.com/profile/11225231402997597739noreply@blogger.com